Q How many liters of an acid solution with no salt content should be mixed with 35 liters of a saline solution with 40% salt content to yield a solution that is 32% salt?

(Target Audience: GMAT)

  1. 4.12
  2. 8.75
  3. 18
  4. 35
  5. 43.75

Answer: Option B

Explanation: Generic Way

Let the quantity of solution with no salt = x

Quantity of salt in 0% saline solution = 0% of x = 0 ltrs

Quantity of salt in 40% saline solution  = 40% of 35 = 14 ltrs.

Total quantity of salt = 0 + 14 = 14 ltrs

Quantity of salt after mixing two solution = 32% of total quantity

      = 32% of (x+35)

Therefore, 14 = 32% of (x+35)

Or, 14 = 32/100*(x+35)

Or, 14*100/32= x+35

Or, x = (14*100/32) – 35 = 8.75 ltrs

OPTION B

 

Explanation: HolaMaven Way